Question

The length of a rectangular-shaped deck 5 meters longer than its width. If the area of the deck is 66^2 what is the length in meters?
A. 6
B. 11
C. 14.
D. 19

Answer 1

The answer is: B. 11

Explanation:

1. The area of a rectangle is:

$A=LW$

Where $L$ is the length and $W$ is the width.

2. The length of the rectangular-shaped deck is 5 meters longer than its width, therefore:

$L=W+5$

3. You must substitute this into $A=LW$:

$66=(W+5)W\\W^{2}+5W-66=0$

4. Now you must solve for the width. You can use the Quadratic formula, which is:

$W=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

Where:

$a=1\\b=5\\c=-66$

5. Subsitute values:

$W=\frac{-5+/-\sqrt{5^{2}-4(1)(-66)}}{2(1)}\\W=6$

6. Then, the lenght is:

$L=6m+5m\\L=11m$