Answer:
A. ![\left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.93%260.07%26%5C%5C0.01%260.99%26%5Cend%7Barray%7D%5Cright%5D)
B. (0.85 0.15)
C. 79.2% population in the city while 20.8% population in the suburb
Step-by-step explanation:
(a) The transition matrix for the information is
C S
(b) the probability vector for the information is
and this gives us
(0.85 0.15)
(c) we simply multiply the above two matrices to find the percent of the population can be expected to be in each category after one year after
![\left[\begin{array}{cc}0.85&0.15\end{array}\right] \left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right] = \left[\begin{array}{cc}0.792&0.208&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.85%260.15%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.93%260.07%26%5C%5C0.01%260.99%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.792%260.208%26%5Cend%7Barray%7D%5Cright%5D)
in the city there are 79.2% while in the suburb, there are 20.8%
Answer:
no solution
Step-by-step explanation:
Simplifying
11q + -6 = 3q + 8q
Reorder the terms:
-6 + 11q = 3q + 8q
Combine like terms: 3q + 8q = 11q
-6 + 11q = 11q
Add '-11q' to each side of the equation.
-6 + 11q + -11q = 11q + -11q
Combine like terms: 11q + -11q = 0
-6 + 0 = 11q + -11q
-6 = 11q + -11q
Combine like terms: 11q + -11q = 0
-6 = 0
Solving
-6 = 0
Couldn't find a variable to solve for.
This equation is invalid, the left and right sides are not equal, therefore there is no solution.
Answer:
7(m-8)
Step-by-step explanation:
We are given: 7 times the difference between m and 8
We want to write an expression. Let’s begin with “the difference between m and 8”.
Difference means subtraction. Therefore, we must subtract m and 8.
(m-8)
Now, let’s add on “7 times”
Times means multiply. Therefore, we must multiply 7 and the expression we just wrote.
7(m-8)
Therefore, 7 times the difference between m and 8 can be written as: 7(m-8)
Answer: Choice C) 10.5
The distance from A to C is 7 units (count out the spaces between the two points, or subtract y coordinates 4-(-3) = 4+3 = 7)
Let AC = 7 be the base of the triangle. You might want to rotate the image so that AC is laying horizontally rather than being vertical.
Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.
base = 7, height = 3
area of triangle = (1/2)*base*height
area of triangle = 0.5*7*3
area of triangle = 10.5 square units
It is 4200 cm hope i helped
