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barxatty [35]
3 years ago
10

g Problem 13. (1.4 points) Which of the following statement is TRUE regarding the dimensionality of the subspace W. (A) It can b

e shown that W = {p(x) ∈ P2 : x dp dx(x) = p(x)} is a subspace of the vector space P2, and the dimension of W is 2. (B) It can be shown that W = A ∈ M2×2 : AB = BA, where B = 1 1 0 1 is a subspace of the vector space M2×2, and the dimension of W is 2. (C) It can be shown that W = x y z ∈ R 3 : x + 2y − 4z = 0 and y − 3z = 0 is a subspace of the vector space R 3 , and the dimension of W is 2. (D) It can be shown that W = A ∈ M2×2 : A T = A is a subspace of the vector space M2×2, and the dimension of W is 2. (E) It can be shown that W = {p(x) ∈ P2 : p(1) = 0} is a subspace of mathcalP2, and the dimension of W is 1.
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer: (C) It can be shown that W = x y z ∈ R 3 : x + 2y − 4z = 0 and y − 3z = 0 is a subspace of the vector space R 3 , and the dimension of W is 2.

Step-by-step explanation:

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let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

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1 year ago
What is the point slope form of a line that has a slope of 3 and passes through point (1,4)?
ser-zykov [4K]
I think its: 4 = 3(1) + b
8 0
3 years ago
What Is the percent equal to 3/10
lianna [129]
30 %
3/10 * 10 = 30/100
30/100= 30%
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3 years ago
Name the property that is illustrated.<br> 1 x 3/4 = 3/4
Tju [1.3M]

Answer:

Associative Property of Addition

5 0
2 years ago
Read 2 more answers
Can someone tell me how they got the answer? I totally forgot how to do this question
pychu [463]
I think it is 128 but not 100%
6 0
3 years ago
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