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Blababa [14]
3 years ago
11

Hey! Can someone help me with this question please, thanks! :)

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Answer:

The answer is y=-2/3x+6

Step-by-step explanation:

Y intercept is at 6 and the graph is going down -2/3 from left to right


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Rosa is thinking of a number between 9.04 and 9.15 that has a 6 in the hundredths place.
Oliga [24]

Answer: 9.06

Step-by-step explanation:

It's the only decimal that has 6 in the hundredths place.

7 0
3 years ago
Read 2 more answers
About 19​% of the population of a large country is hopelessly romantic. If two people are randomly​ selected, what is the probab
Aleksandr-060686 [28]

Answer:

3.61% probability that both are hopelessly romantic​.

34.39% probability at least one is hopelessly romantic

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are hopelessly romantic, or they are not. The probability of a person being hopelessly romantic is independent from other people. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

19​% of the population of a large country is hopelessly romantic.

This means that p = 0.19

Two people are randomly​ selected

This means that n = 2

What is the probability both are hopelessly romantic​?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

3.61% probability that both are hopelessly romantic​.

What is the probability at least one is hopelessly romantic​?

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.19)^{1}.(0.81)^{1} = 0.3078

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.3078 + 0.0361 = 0.3439

34.39% probability at least one is hopelessly romantic

7 0
3 years ago
How do I solve the formula S=3F-24 for F
adell [148]

s=3f-24

add 24 to each side

s+24 =3f

divide by 3

(s+24)/3 = f

Answer: f=(s+24)/3  or 1/3 s +8

3 0
3 years ago
Help i dont know how to do this !!!!!!!!!!!! for brainlist
valentinak56 [21]

Answer:

We can simplify everything to the power of 2:

8^{x+2} = 2^{3*(x+2)}=2^{3x+6

16^{x+1} = 2^{4*(x+1)}=2^{4x+4

As the two equations are equal to each other and they have common bases, their powers must be equal too. We can come up with this equation:

3x+6=4x+4

solve for x

x=2

D (last answer choice)

plug x=2 in and check and you will get 4096=4096

5 0
2 years ago
Round to the hundredth 3.5262
lubasha [3.4K]
3.53 that’s the answer
6 0
3 years ago
Read 2 more answers
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