Step-by-step explanation:
No. of banana Cost Unit price
4 2 0.50
6 3 0.50
7 3.5 0.50
20 10 0.50
20 10 0.50
33 16.50 0.50
Cost = No of banana x unit price
Cost = 4 x 0.50 = 2
Cost = 6 x 0.50 = 3
Cost = 7 x 0.50 = 3.50
Cost = 20 x 0.50 = 10
No of banana = Cost / Unit price
No of banana = 10 / 0.50 = 20
No of banana = 16.50 / 0.50 = 33
Answer:
<h3>The surface area in square meters that Darren has to paint is
</h3><h3>∴
</h3>
Step-by-step explanation:
Given that Darren is painting a wooden block is a rectangular prism
Its length is 12 cm ,width is 9 cm and height is 5 cm
<h3>To find the surface area in square meters that Darren has to paint :</h3>
Let l be the length, w be the width and h be the height
Then l=12 cm , w=9 cm and h=5 cm
The formula for the Surface area is
A=2(lw+wh+hl) square units
Substitute the values in formula we get,
A=2(12(9)+9(5)+5(12))
=2(108+45+60)
=2(213)
=426
<h3>∴
</h3><h3>∴ the surface area in square meters that Darren has to paint is
</h3>
Answer:
Your answer for F will be 13.
Step-by-step explanation:
Take 11.2 and add it to 1.8, and you will get 13 and 13 will be the variable (f). So, f (13) - 1.8 = 11.2
Hope this helps! :D
Answer: x > 5
Step-by-step explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.
Since 3 is being subtracted from x, we add 3 to
both sides of the inequality to get x > 5.
When graphing x > 5, we have an open circle on 5 and the
open circle tells us that 5 is not part of our answer.
Then we draw an arrow going to the right to represent
all possible solutions to this inequality, any number greater than 5.
Answer: 5 feet
Step-by-step explanation: A rectangle is a quadrilateral with 4 sides. The opposite sides are parallel and have the same length.
Top and bottom of the window are opposite, so they have the same measure of 3 feet.
One length of the window is 5 feet. Since the last side is opposite to the length of the window, it has the same length, i.e., its value is 5 feet.
