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3 years ago

Helppppppppppppppppp

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Option D:

k = –2

Solution:

Let y = f(x).

Direct variation:

A relationship between two variables in which one is a constant multiple of the other.

y varies constantly means that y = kx.

The constant $k=\frac{y}{x}$ .

Substitute x = –1 and y = 2 from the table.

$$k=\frac{2}{-1}=-2$

Substitute x = 2 and y = –4 from the table.

$$k=\frac{-4}{2}=-2$

Substitute x = 5 and y = –10 from the table.

$$k=\frac{-10}{5}=-2$

Therefore k = –2.

Option D is the correct answer.

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hodyreva [135]

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3 years ago

If n + 7 = 10, evaluate 2n - 2 O 3 0 17 4 6

Alexandra [31]

Answer:

The value of 2n - 2 is 4.

Step-by-step explanation:

Given the equation

$n + 7 = 10$

Subtract 7 from both sides of the equation

$n+7-7=10-7$

Simplify

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Now substituting n = 3 in the equation

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Therefore, the value of 2n - 2 is 4.

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3 years ago

Write the standard equation of a circle with center (-2,5) and the point (4,13) on the circle

n200080 [17]

since the point (4,13) is on the circle, then the distance from the center to it, is the radius of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{13})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-2)]^2+[13-5]^2}\implies r=\sqrt{(4+2)^2+(13-5)^2} \\\\\\ r=\sqrt{36+64}\implies r=\sqrt{100}\implies r=10 \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad radius=\stackrel{10}{ r}\\[2em] [x-(-2)]^2+[y-5]^2=10^2\implies (x+2)^2+(y-5)^2=100$

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3 years ago

HELPPPPPPPPPPPPPPPOO

AURORKA [14]

To do the comparison, we'll use the following temperatures:

Day 1: 5°F

Day 2 : 1.5°F

Comparison of Day 1 and Day 2:

$1.5F$

$5F>1.5F$

Comparison of days with absolute value:

$1.5F$

$5F>1.5F$

The temperature that's the closest to 0 during the week is -0.5°F. Using absolute value, we can see that the distance from 0°F to -0.5°F is the smallest of all the temperature measurements.

The temperature that's the farthest to 0 during the week is 5°F. Using absolute value, we can see that the distance from 0°F to 5°F is the biggest of all the temperature measurements.

The coldest temperature is -4°F. This is the value that is farthest to the left of 0°F on the number line.

The warmest temperature is 5°F. This is the value that is farthest to the right of 0°F on the number line.

8 0

2 years ago

Suppose your average, after taking 4 quizzes, is 71 (out of 100). what must your average be on the next 5 quizzes to increase yo

Anton [14]

Short answer: 98
Remark
when you have an average of 71, it's like saying that you took 4 quizzes and got 71 on all of them.
Step One
Find the total point count for the 4 quizzes.
T_4 = 71 * 4 = 284

Step Two
Create an equation that will give you the necessary point count to average 86.

284 + 5*x = 86 * 9
Why did we do this? It is because you have 9 quizzes altogether. All nine must be something that gives a point count of 86 on each quiz. You have to put together 9 such quizzes with a total count of 774.

Step three
Solve the equation.
284 + 5x = 774 Subtract 284 from both sides.
5x = 774 - 284
5x = 490 Divide by 5
x = 490/5
x = 98

You must get an average of 98 on the next 5 quizzes

Answer: 98 <<<<<

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3 years ago