Question

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Answer 1

Option D:

k = –2

Solution:

Let y = f(x).

Direct variation:

A relationship between two variables in which one is a constant multiple of the other.

y varies constantly means that y = kx.

The constant $k=\frac{y}{x}$.

Substitute x = –1 and y = 2 from the table.

$k=\frac{2}{-1}=-2$

Substitute x = 2 and y = –4 from the table.

$k=\frac{-4}{2}=-2$

Substitute x = 5 and y = –10 from the table.

$k=\frac{-10}{5}=-2$

Therefore k = –2.

Option D is the correct answer.