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Sliva [168]
3 years ago
5

You are observing different tissue samples and classifying the cells into their respective stage in the cell cycle. What can you

conclude about Sample B based on these observations? A) Sample B Is is most likely cancerous because most of the cells are in interphase. B) Sample B is most likely cancer tissue because most cells are in some stage of mitosis. C) Sample B is most likely a normal tissue sample because most of the cells are in interphase. D) Sample B is most likely a normal tissue sample because most cells are in some stage of mitosis.
Biology
2 answers:
bonufazy [111]3 years ago
4 0

D) Samples A & C indicate cancer due to the large proportion of cells in some stage of mitosis compared to the cells in interphase.  

Sample: Number of Cells in Interphase Number of Cells in Prophase Number of Cells in Metaphase Number of Cells in Anaphase Number of Cells in Telophase

Sample A 6 15 4 7 8

Sample B 25 4 2 3 1

Sample C 4 9 5 3 6

svp [43]3 years ago
3 0

We have been given that different tissue samples are in their respective stage  of cell cycle.

Ans is option B because cancerous cells tend to divide indefinitely regardless of the presence or absence of growth factors. In cancerous cells G0 check points fail and the cells are always in some stage of mitosis i.e. cell is supposed to be in any of the following stages of mitosis :

1) Prophase

2) Metaphase

3) Anaphase

4) Telophase

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In humans, MN blood types are determined by an autosomal gene with two alleles: LM and LN. In one population of 592 people, ther
RoseWind [281]

Answer:

148

Explanation:

According to Hardy-Weinberg equilibrium,

p + q = 1

p² + 2pq + q² = 1 where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of homozygous dominant genotype

2pq = frequency of heterozygous genotype

q² = frequency of homozygous recessive genotype

Here,

Total population = 592

Number of NN people = 148

Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25

q = √0.25 = 0.5

p = 1 - q

= 1 - 0.5 = 0.5

Hence, p = 0.5

Frequency of MM genotype = p² = 0.25

Number of people with MM genotype = 0.25*592 = 148

Hence, 148 people will have MM genotype or M blood group.

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