The line containing the vector <em>q</em> can be obtained by scaling <em>q</em> by an arbitrary scalar <em>t</em>. To make this line pass through the point <em>p</em>, translate this line by a vector <em>p</em> pointing from the origin to <em>p</em>.
So the line we want has equation
<em>r</em>(<em>t</em>) = <em>q</em><em>t</em> + <em>p</em> = (14, -8)<em>t</em> + (-4, 12) = (14<em>t</em> - 4, 12-8<em>t</em>)
where <em>t</em> is any real number.
In a kite, the diagonals intersect normally. Hence, we also know that XV= 4cm, half of XZ. This is because the triangle XVY and XVW are equal, but it is a general property of kitest. XVY is the right angle in this. We can use then trigonometry to calculate VY.
We have that tan30= opposite site of angle XYV/adjacent leg by the definition of the tangent. Hence tan30= XV/YV. Thus, substituting the value of the tangent:
Answer:
0.25y
Step-by-step explanation:
Y/4 is = to 0.25y