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Rudik [331]
3 years ago
6

what is the equation of the line that is parallel to the line y=-1/3x+4 and passes through the point(6,5)

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

y= -1/3x+7

Step-by-step explanation:

Lines that are parallel have the same slope.  Therefore the line of the equation that you are finding has the slope = -1/3 and an unknown value we can call b to create the equation y=-1/3x +b.

Using the point which the line must pass (6,5), we can plug x and y into the unknown equation to solve for b, the y-intercept.


5=-1/3(6)+b

5=-2+b

7=b

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What is the slope of a line that is perpendicular to the line 2y – 3x = 8?
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Answer:

\frac{-2}{3}

Step-by-step explanation:

2y - 3x = 8

2y = 3x + 8

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It is similar to y = mx + b

Therefore m = \frac{3}{2}

To check whether a line has perpendicular slope we check the product of the slopes to be -1.

The perpendicular slope is \frac{-2}{3}

7 0
3 years ago
The graph below shows a line segment MN: Which of the following equations best represents the line segment MN?
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Aneli [31]

Answer:

It's the last choice:

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Using the point-slope form to find  the required equation:

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y + 7 = -2(x - 4)

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4 years ago
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