The correct answer for the given statement above would be TRUE. It is true that there is no solution to the equation sec x = 0. Why?
<span>Sec(x) is actually 1/cos(x), which can't be absolute zero. Cos(x) ranges between -1 and 1; it would have to be unbounded for sec(x) to reach 0, or in short, it is undefined. Hope this answer helps. </span>
Step-by-step explanation:
x=14-6y/3
substituting x=14-6y/3 into eqn 2
2(14-6y/3)+8y=2
multiplying through by 3
2(14-6y/3)×3 +8y×3=2×3
2(14-6y)+24y=6
28-12y+24y=6
28-12y=6
28-6=12y
22=12y
22/12=y
finding x
2x+8(22/12)=2
2x+44/3=2
2x=2-44/3
x=(-38/3)/2
×=-38/6
3 is the max number of games she could buy
75-28 leaves 47 left divide by 15 per game
Answer:
B
Step-by-step explanation:
give me brainliest 5 star and thank!
