Question

1)simplify the expression (2x)^4 2)the perimeter of a rectangular is twice the sum of its length and its width. the perimeter is 16 meters and its length is 2 meters more then twice its width 3)Find the real numbers x and y that make the equation true.
-3 + yi = x + 6i

Answer 1

$(2x)^4=16x^4$
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$2(l+w)=16\\ l=2w+2\\\\ 2(2w+2+w)=16\\ 6w+4=16\\ 6w=12\\ w=2\\\\ l=2\cdot2+2\\ l=6$
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$-3+yi=x+6i\Rightarrow x=-3 \wedge y=6$