Answer:
True
Explanation:
A computer can be defined as an electronic device that is capable of receiving of data in its raw form as input and processes these data into information that could be used by an end user.
Generally, a computer is composed of five (5) main components and these include;
I. Input unit.
II. Output unit.
III. Central processing unit (CPU).
IV. Storage (memory) unit.
V. Power supply unit (PSU).
A power supply also referred to as power supply unit (PSU) can be defined as a hardware component of a computer that converts and step-down the domestic alternating current (AC) electrical power to a low-voltage regulated direct current (DC) power, so that the internal components of a computer can be supplied with power.
Hence, the power supply unit (PSU) serves as a rectifier by converting alternating current (AC) house current to direct current (DC) and as a transformer to step-down voltage from 220 Volts or 110 Volts to 50, 30, or 20 Volts depending on the requirements of a computer.
Answer:
The answer is "Confidentiality".
Explanation:
Data Security is also known as protection against unauthorized computer access, files, and pages through digital information protection. The protection of data also prevents data from bribery.
- It applies to both the security of data from unwanted entities being obtained.
- It allows accessing sensitive data, which may be able to do so.
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
The answer is <em>B.) Close Range Drones</em>
I just took the test
