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Gre4nikov [31]
3 years ago
7

Find two numbers a+b is -4 and difference a-b is 4 what's your answer

Mathematics
1 answer:
Trava [24]3 years ago
6 0

Answer:

a=0, b=-4

Step-by-step explanation:

a+b=-4.....(1)

a-b=4.......(2)

(1)+(2): 2a=0

a=0

0+b=-4

b=-4

(a, b) =(0,-4)

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I need help solving this!
blagie [28]

Answer:

miles hybrid car went = 9.80 gal × 54.1 miles/gal

= 530.18 miles

132km × 0.621 = 81.972 miles

530.18 miles = 9.80 gal

1 mile = 9.80/530.18

= 0.018 gal

81.972 miles = 0.018 × 81.972

= 1.515 gal

1.515 gal × 3.785 = 5.734 litres

3 0
3 years ago
Given g(x)= -2x+2 and f(x)= 3x^2+4, find (g+f)(-3)
aliina [53]

Answer:

39

Step-by-step explanation:

g(x)= -2x+2 and f(x)= 3x^2+4

(g+f)(-3)

g(-3) = -2(-3) +2 = 6+2 =8

f(-3) = 3 (-3)^2 +4 = 3(9)+4 = 27+4 = 31

(g+f)(-3) = g(-3) + f(-3) = 8+31 = 39

3 0
3 years ago
9 inches of ribbon are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbon?
netineya [11]

Answer:

a total of 24 presents can be wrapped

Step-by-step explanation:

6 x 3 = 18 feet of ribbon

18 x 12 = 216 inches of ribbon

216/9 = 24 presents can be wrapped

3 0
3 years ago
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
I need help on this math problem ​
abruzzese [7]

Answer:

for the first one, simply add g(x) and h(x) :

x+3 + 4x+1 = 5x + 4

the second one, you would multiply them :

(x+3)(4x+1) = 4x^2 + 13x + 3

the last one, you would subtract :

(x+3)-(4x+1) = -3x + 2

and then substitute 2 for 'x' :

-3*2 + 2 = -6 + 2 = -4

8 0
3 years ago
Read 2 more answers
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