In(xy) = e^(x+y)
(xy)'/xy = (x+y)' e^(x+y)
(x'y + xy')/xy = (1+y') e^(x+y)
(y + xy')/xy = (1+y')e^(x+y) and simplify
Hope this helps
A nonlinear function that can be written on the standard form
<span><span>a<span>x2</span>+bx+c,wherea≠0</span><span>a<span>x2</span>+bx+c,wherea≠0</span></span>
is called a quadratic function.
All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is
Since you are subtracting 2 logs, you write the single log as a quotient.
Step-by-step explanation:
hope it is helpful to you
