Find the cosine of ∠T.
1 answer:
ANSWER: ∠T = 32.4°
Remember the formula for the basic trig functions: SOH CAH TOA
Since you want to find cosine for <T, you need the adjacent side length as well as the hypotenuse's length which can be found using the Pythagoras's Theorem with <em>a </em> and <em>b</em> being the side lengths and <em>c</em> being the hypotenuse.
Using the theorem, we get c=37
Now use the cosine formula to get <T = 12/37 to get the final answer.
You might be interested in
Remember
for F(x) is the antiderivitive of f(x)
so find the antiderivitive of ((x+1)^2)/x
if we expand we get (x^2+2x+1)/x which simplifies to x+2+(1/x)
the anti-deritivive of x is (1/2)x^2
the antideritiveve of 2 is 2x
the antideritivieve of 1/x is ln|x|
F(x)=(1/2)x^2+2x+ln|x|+C
F(1)=(5/2)+ln1+C
F(2)=6+ln2+C
F(2)-F(1)=6+ln2+C-(5/2+ln1+C)
F(2)-F(1)=(7/2)+ln2
that is the answer
if you want is simplified or expanded it is about 4.1915
for F(x) is the antiderivitive of f(x)
so find the antiderivitive of ((x+1)^2)/x
if we expand we get (x^2+2x+1)/x which simplifies to x+2+(1/x)
the anti-deritivive of x is (1/2)x^2
the antideritiveve of 2 is 2x
the antideritivieve of 1/x is ln|x|
F(x)=(1/2)x^2+2x+ln|x|+C
F(1)=(5/2)+ln1+C
F(2)=6+ln2+C
F(2)-F(1)=6+ln2+C-(5/2+ln1+C)
F(2)-F(1)=(7/2)+ln2
that is the answer
if you want is simplified or expanded it is about 4.1915