Question

Mason used 1/6 of a gram of honey to make 1/12 of a pan of pudding. How many grams are needed to make a full pan of pudding?

Answer 1

Answer:

2 grams

Step-by-step explanation:

Given,

Quantity of honey required for $\frac{1}{12}$ part of pudding = $\frac{1}{6}$ grams,

Since, total part of pudding = 1,

The number of $\frac{1}{12}$ parts in the pudding = 12,

So, the number of gram of honey needed for 1 full part of pudding = number of $\frac{1}{12}$ parts × honey required for $\frac{1}{12}$ part,

= 12 × $\frac{1}{6}$

= $\frac{12}{6}$

= 2

Answer 2

so with 1/6 gram of honey you can make 1/12 pan of pudding

that means with 6/6 or 1 gram of honey you can make 6/12 pan of pudding

then 2 gram of honey is needed to make 12/12 or 1 full pan of pudding