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stich3 [128]
3 years ago
7

How can the common difference between 375-315=30

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0
Hello :
in the arithemitic sequence  : an = an-1 + 30
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The sum of two numbers is 25 and their quotient is 4
insens350 [35]

Answer:

20 and 5

Step-by-step explanation:

20+5=25

20÷5=4

7 0
2 years ago
What does the line of -4 x + 3y = 6 look like
Llana [10]

Answer:

The line slopes upwards from left to right wit a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2

Step-by-step explanation:

We first rearrange the equation to the order y=mx+c where m is the gradient and c the y intercept.

3y=4x+6

y=(4/3)x+2

The gradient is therefore 4/3 and the y intercept is 2.

At the c intercept, y=0

0=(4/3)x +2

(4/3)x=-2

x=-2×3/4

=3/2

The line slopes upwards from left to right with a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2

8 0
2 years ago
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The surface areas of two similar solids are 169 m2 and 81 m2. the volume of the larger solid is 124.92 m3. which proportion corr
ikadub [295]

By finding the scale factor, we will see that the volume of the smaller solid is 86.75 m³.

<h3>How to get the volume of the smaller solid?</h3>

If the solids are similar, then there is a scale factor between the two. Then the relation between the areas is equal to the scale factor squared, and the relation between the volumes is equal to the scale factor cubed.

This means that if the areas are 169 m² and 81 m², then we can write:

169 m² = (k²)*81 m²

Solving for k, we get:

k = √(169 m²/81 m²) = 1.44

Then if the volume of the large solid is 124.92m³ we can write:

124.92m³ = k³*V

Replacing k and solving for V we get:

124.92m³ = (1.44)³*V

(124.92m³/ (1.44)³) = V = 86.75 m³

If you want to learn more about scale factors:

brainly.com/question/3457976

#SPJ4

6 0
2 years ago
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In which quadrant does the point (–10, –9) lie
ludmilkaskok [199]
The 3rd quadrant bc they are both negative points
5 0
2 years ago
WILL GIVE BRAINLIST
Nataliya [291]

Answer:

Step-by-step explanation:

Find out the  how much chlorine is in the pool .

To prove

As given

The amount of chlorine in a swimming pool varies directly with the volume of water.

The pool has 2.5 milligrams of chlorine per liter of water.

i.e

2.5 milligrams of chorine = 1 litre of water

There are 8000 gallons of water in the swimming pool.

As 1 gallons = 3.78541 litre (Approx)

Now convert 8000 gallons of water in litres.

8000 gallons = 8000 × 3.78541 litre

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Now calculate chlorine in the pool for 30283.28 litres  of waters.

As

2.5 milligrams of chlorine = 1 litre of water

2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water

75708.2 milligrams of chlorine for 30283.28 litre of water .

5 0
2 years ago
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