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musickatia [10]

3 years ago

9

7 3 3 ( 2 3 − 1 3 ) 2 simplify

1 answer:

Nadya [2.5K]3 years ago

5 0

14660 733-10x2 just add it all together and simplify

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What is .744 as a fraction

jenyasd209 [6]

744/1000 would be your answer

4 0

3 years ago

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McSaw’s Ice Cream makes muffins that cost $.60 each. Past experience shows that 10% of the muffins will become stale and have to

Temka [501]

.60×.55=.33 cent mark up to original price
.60+.33=.93 cost per muffin

.6×100=60×.55=93 cost for 100 muffins
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4 0

2 years ago

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jek_recluse [69]

3/5 I think is the right number because there’s 60 boys and only 36 of them have a pet.

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Work out the value of x <br>

GREYUIT [131]

A full circle is 360°.

x + 3x + 90° = 360°

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6 0

3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Tom [10]

Stokes' theorem says the integral of the curl of $\vec F$ over a surface $S$ with boundary $C$ is equal to the integral of $\vec F$ along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

$\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

We have

$\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=4\,\vec k$

Parameterize the ellipse $S$ by

$\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath$

with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k$

Then the flux of the curl is

$\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}$

4 0

3 years ago