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3 years ago

4. Find the value of x in the right triangle below. 60°

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

It is worthwhile memorizing the ratios of legs in a 30°–60°–90° triangle. Shortest to longest, the ratios are ...

1 : √3 : 2

Then the sides marked will have the ratio ...

6 : x = 1 : 2 = 6 : 12

x = 12

_____

You can also get there using trigonometry.

cos(60°) = 6/x

x = 60/cos(60° = 60/0.5

x = 12

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Lakeview is 101 miles from Springfield. Irania must go to the law library in Springfield to get a document for the law firm for

Arlecino [84]

Answer: Approximately 4.1224 hours

4.1224 hours = 4 hours, 7 minutes, 21 seconds approximately

===========================================

Work Shown:

d = distance = 2*101 = 202 miles

r = rate or speed = 49 mph

t = time = unknown

d = r*t

202 = 49*t

49t = 202

t = 202/49

t = 4.1224 hours approximately

--------------

If you want to convert to hours,minutes,seconds, then...

4.1224 hours = 4 hours + 0.1224 hours

4.1224 hours = 4 hours + (0.1224*60) min

4.1224 hours = 4 hours + 7.344 min

4.1224 hours = 4 hours + 7 min + 0.344 min

4.1224 hours = 4 hours + 7 min + (0.344*60) sec

4.1224 hours = 4 hours + 7 min + 20.64 sec

4.1224 hours = 4 hours + 7 min + 21 sec ..... approximate

4.1224 hours = 4 hours, 7 min, 21 sec .... also approximate

Note: this time value is driving time only. It does not take into account any time spent at the law library or any other stops.

4 0

3 years ago

Please simplify -8(-3a-2)

Misha Larkins [42]

Answer: 24a+16

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is

garik1379 [7]

Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

$\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}$