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vlada-n [284]
3 years ago
6

What is the slope-intercept form of the function that contains the point (8, 12) and has a slope of −2?

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0
In order to change this into slope-intercept form you need to distribute the .-2 into the parenthesis and then add the 12 to the right side. Let me know if that helps!<span />
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Give an example of a rigid object
Ann [662]

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Summarize rigid body simulation.

5 0
3 years ago
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What is the range of the function g(x)=[x]+1
Lerok [7]

<em>Assuming [x] means the closest integer to x</em>

Answer:

(-\infty, \infty)

Step-by-step explanation:

We can see that for any integer x, there will always be a [x], so there will always be a [x]+1. So, we don't need to worry about the domain impacting the range.

[x] can be any integer from -\infty to \infty, and as \infty+1=\infty(at least in terms of a function's range and domain), the range of [x]+1 is equal to the range of [x], which is (-\infty, \infty).

So, the answer is \boxed{(-\infty, \infty)} and we're done!

6 0
2 years ago
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What is the equation of the line that passes through (-2,3) and is parallel to 2x+3y=6?
Vsevolod [243]

Answer:

<h2>2x + 3y = 5</h2>

Step-by-step explanation:

\bold{METHOD\ 1:}

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

Let k:y=m_1x+b_1,\ l:y=m_2x+b_2

then

l\ \parallel\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have the equation of a line:

2x+3y=6

Convert to the slope-intercept form:

2x+3y=6           <em>subtract 2x from both sides</em>

3y=-2x+6              <em>divide both sides by 3</em>

y=-\dfrac{2}{3}x+2\to m_1=-\dfrac{2}{3}

therefore the slope is m_2=-\dfrac{2}{3}

Put the value of the slope and the coordinates of the point (-2, 3) to the equation of a line:

3=-\dfrac{2}{3}(-2)+b

3=\dfrac{4}{3}+b            <em>subtract 4/3 from both sides</em>

\dfrac{9}{3}-\dfrac{4}{3}=b\to b=\dfrac{5}{3}

Finally:

y=-\dfrac{2}{3}x+\dfrac{5}{3}

Convert to the standard form (Ax + By = C):

y=-\dfrac{2}{3}x+\dfrac{5}{3}              <em>multiply both sides by 3</em>

3y=-2x+5           <em>add 2x to both sides</em>

2x+3y=5

\bold{METHOD\ 2:}

Let k:A_1x+B_1y=C_1,\ l:A_2x+B_2y=C_2.

Lines <em>k</em> and <em>l</em> are parallel iff

A_1=A_2\ \wedge\ B_1=B_2\to\dfrac{A_2}{A_1}=\dfrac{B_2}{B_1}

We have the equation:

2x+3y=6\to A_1=2,\ B_1=3

then the equation of a line parallel to given lines has the equation:

2x+3y=C

Put the coordinates of the point (-2, 3) to the equation:

C=2(-2)+3(3)\\\\C=-4+9\\\\C=5

Finally:

2x+3y=5

4 0
3 years ago
Find the area under the standard normal distribution curve between z = 0 and z = 2.16.
Vladimir79 [104]

do you have a z table chart to look at?

 find Z= 0 should show that z=0 = 0.500

and z=2.16 = 0.9846

 subtract them

0.9846-0.500 = 0.4846 is the area

7 0
3 years ago
plzzzzz i vill give 5 stars a heart brainlyest if you can anwser this write 5(2j+3+1j)= using the commutive property
tatuchka [14]

Answer:

The answer would be 5 (3j + 3)

Step-by-step explanation:

The 5 outside the partheness would stay the same

2j + 1j = 3j

The 3 remains the same.

So our answer is

5(3j + 3)

5 0
3 years ago
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