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7nadin3 [17]
3 years ago
12

Please help will mark brainiest: Find the area of the following shapes:

Mathematics
2 answers:
ladessa [460]3 years ago
5 0

Answer:

180

Step-by-step explanation:

1- you can take the rectangular part of the shape because it is easy to calculate: length×width which is 9×15= 135

2- Now you take the triangular part of the shape which you can calculate by width×length× 1/2. The width is 15-9= 6 so 6×15×1/2= 45

3- Add them together to get the full area 45+135= 180

elena-s [515]3 years ago
4 0

Answer:

180

Step-by-step explanation:

Find the area of the imaginary square. Then subtract it by the area of the space left in.

  1. 15*15
  2. 6*15 divide by 2
  3. 225-45
  4. 180
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Pls help (kinda easy)
3241004551 [841]

Answer:

f(x)=(2x+1)(2x-1).

Step-by-step explanation:

We want to convert the function into the form that let's us easily find the x-intercept, and it would be for the form (ax+b)(cx+d) because then we can find the x-intercept in the following manner:

(ax+b)(cx+d)=0

x=-b/a

x=-d/c

We factor our function f(x)=4x^2-1 and get

\boxed{f(x)=(2x+1)(2x-1)}

Now this form let's us easily find the x-intercepts:

x=-1/2

x=1/2

and so we pick the second choice: f(x)=(2x+1)(2x-1).

5 0
3 years ago
Read 2 more answers
Sterile fruit flies are used in an experiment where the proportion that survives at least days is given by . if the experiment b
Nana76 [90]

Answer:

Number of fruit flies after 14 days is equal to 1880.

Step-by-step explanation:

given,

fruit flies at the beginning of the experiment = 200 fruit flies

rate of increase of fruit flies = 5 per hour

to calculate the number of flies after 14 days.

time = 14 days = 14 × 24 = 336 hours

flies after 14 days = initial number of flies + rate of increase  × time

                             = 200 + 5 × 336

                             = 1880 fruit flies.

hence,Number of fruit flies after 14 days is equal to 1880.

4 0
3 years ago
Hey guys can I get a little help on this problem please, thank you.​
DedPeter [7]
Point g because it’s in the middle.

midpoint= the middle.
5 0
2 years ago
The diameter of the sun is about 1.4x10^6 km. The diameter of the planet Mars is about 7000 km. What is the approximate ratio of
Alborosie

Answer:

b is the correct answer

5 0
4 years ago
In Lake Erie, walleye fish are abundant. The lengths of walleyes follow a Normal distribution with a mean of 31 inches and a sta
AlladinOne [14]

Answer:

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 31

Standard deviation = 3.6

a. Approximately 32% of walleyes have lengths less than 27.4 inches.

27.4 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of the other 32% more than 1 standard deviation from the mean, 16% of the lengths are less than 27.4 and 16% are greather than 31+3.6 = 34.6.

So approximately 16% of walleyes have lengths less than 27.4 inches, which means that this statement is false.

b. Approximately 95% of walleyes have lengths greater than 23.8 inches.

23.8 is two standard deviations below the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths lower than 23.8 and 100-2.5 = 97.5% have lengths greater than 23.8, which means that this statement is false.

c. Approximately 16% of walleyes have lengths longer than 38.2 inches.

38.2 is two standard deviations above the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths longer than 38.2 inches, which means that this statement is false.

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

34.6 is one standard deviation above the mean.

The empirical rule is symmetric, which means that 50% of the measures are above the mean and 50% of the meausures are below the mean.

Also, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So, 50% below the mean, plus 34% between the mean and 34.6 means that approximately 84% of the walleyes have lengths less than 34.6 inches, which means that this statement is true.

e. Approximately 2.5% of walleyes have lengths between 31 inches and 34.6 inches.

31 is the mean

34.6 is one standard deviation above the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So 34% of walleyes have lengths between 31 inches and 34.6 inches, which means that this statement is false.

5 0
4 years ago
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