The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:
S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
Answer:
angle 9 measures 105 degrees
Step-by-step explanation:
measure of angle 8 is congruent to measure of angle 11 (alternate-interior angles are congruent)
measure of angle 11 is congruent to measure of angle 9 (corresponding angles are congruent)
therefore, measure of angle 8 = measure of angle 9
Answer:
Step-by-step explanation:
We are given the function:
And we want to determine:
Substitute:
![\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7Dg%28x%20%2B%20a%29%20-%20g%28x%29%20%26%3D%5Cleft%5B5%28x%2Ba%29%5E2%20%2B%202%28x%2Ba%29%5Cright%5D%20-%5Cleft%5B5x%5E2%2B2x%5Cright%5D%20%20%20%20%5Cend%7Baligned%7D)
And simplify:
![\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7Dg%28x%20%2B%20a%29%20-%20g%28x%29%20%26%3D%5Cleft%5B5%28x%2Ba%29%5E2%20%2B%202%28x%2Ba%29%5Cright%5D%20-%5Cleft%5B5x%5E2%2B2x%5Cright%5D%20%5C%5C%20%20%5C%5C%20%26%3D%20%5Cleft%285%28x%5E2%20%2B%202ax%20%2B%20a%5E2%29%20%2B%20%282x%20%2B%202a%29%20%5Cright%29%20%2B%20%5Cleft%28-5x%5E2%20-%202x%5Cright%29%20%5C%5C%20%5C%5C%20%26%3D%20%5Cleft%28%285x%5E2%20%2B%2010ax%20%2B%205a%5E2%29%20%2B%20%282x%20%2B%202a%29%5Cright%29%20%2B%20%5Cleft%28-5x%5E2%20-%202x%5Cright%29%20%5C%5C%20%5C%5C%20%26%3D%20%285x%5E2-5x%5E2%29%20%2B%20%2810ax%20%2B%202x%20-%202x%29%20%2B%20%285a%5E2%2B2a%29%20%20%20%20%20%5C%5C%20%5C%5C%20%26%3D%2010ax%20%2B%205a%5E2%20%2B%202a%20%5Cend%7Baligned%7D)
In conclusion:
