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3 years ago

What does csc x cot x (1-cos^2 x) equal

Mathematics

2 answers:

OLEGan [10]3 years ago

8 0

Answer:

Step-by-step explanation:

IceJOKER [234]3 years ago

3 0

Answer:

csc (x) cot (x), sin^2 (x)

Step-by-step explanation:

I hope this helps!

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I need help with this math question

kirill115 [55]

Answer:

Step-by-step explanation:

6 0

2 years ago

In Δ,∠=70°,∠=50° ∠ . <br> ℎ ∠.

AveGali [126]

Answer:

100°

Step-by-step explanation:

A triangle is a polygon shape with three sides. Triangles are of different types such as obtuse, scalene, equilateral, isosceles etc.

In triangle ABC:

70° + 50° + ∠C = 180° (sum of angles in a triangle)

120 + ∠C = 180

∠C = 180 - 120

∠C = 60°

Since ∠C is bisected into ∠ACD and ∠BCD, hence:

∠ACD = ∠BCD = ∠C / 2

∠ACD = ∠BCD = 60 / 2

∠ACD = ∠BCD = 30°

In triangle ACD:

∠A + ∠ACD + ∠ADC = 180° (sum of angles in a triangle)

50 + 30 + ∠ADC = 180

∠ADC + 80 = 180

∠ADC = 100°

6 0

3 years ago

What is the proper way to check an algebraic solution?

vlabodo [156]

The correct way is to plug in the answer back into the equation and see if it results in the correct solution.

4 0

3 years ago

Read 2 more answers

Khan Academy btw

Irina-Kira [14]

Answer:

B and D

Step-by-step explanation:

$\frac{2^{5} }{6^{5} } = (\frac{1}{3} )^{5}$

$\frac{2^{5} }{6^{5} } = 2^{5}*6^{-5}$

3 0

3 years ago

A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam

bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against H_1 if obs. $T > t_{\alpha /2;n-1}$

here obs.T=1.879

$\therefore obs.T \ngtr 2.447=t_{0.025;6}$

we accept $H_o:\mu _{1}=\mu_{2}$ at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that $X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2})$ independently

We want to test $H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}$

define $D_i=X_i-Y_i , i=1(1)8$

now $D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8$

the hypothesis becomes

$H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0$

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0

3 years ago