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2 years ago

UPUUVITICII

Mathematics

1 answer:

kondor19780726 [428]2 years ago

7 0

Answer:

perimeter=25.12 ft

Area=50.24 ft^2

Step-by-step explanation:

Radius=4 feet

π=3.14

Perimeter=2 x π x Radius

Perimeter=2 x 3.14 x 4

Perimeter=25.12 feet

Area=π x radius x radius

Area=3.14 x 4 x 4

Area=50.24 ft^2

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What is the length of the line segment between point (-5,8) and point (-5,-4).

dedylja [7]

Answer:

12 would be the distance between the two points

Step-by-step explanation:

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9 -4n+ 3n = 8n + 3 -3

ArbitrLikvidat [17]

Answer:

Answer:

n = 1

Step-by-step explanation:

This equation is just basic alegebra. First, combine like terms to get

9 - n = 8n. (Because 3 - 3 = 0, and -4n + 3n = -n.) Now the equation is much simpiler; add n to both sides to get 9 = 9n. Divide 9 by both sides to get that n = 1.

You can check your answer by plugging 1 in for n.

9 - 4(1) + 3(1) = 8(1) + 3 - 3

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Therefore, n is proven to equal 1.

Hope this is helpful kid sorry i went very far yesterday hope you can forgive me but Anyways here it is <3

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2 years ago

What ratio can we say are equivalent to 2:9 how do you get the answer explain to me

Ulleksa [173]

Ratio equivalent to 2:9 is 4:18, 6:27

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2 years ago

Solve for x: (X+1)(x-3) = 0

Anton [14]

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Step-by-step explanation:

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2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

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3 years ago