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olga2289 [7]
4 years ago
14

Composite number between 60 and 80

Mathematics
2 answers:
Aneli [31]4 years ago
7 0
62<span>, </span>63<span>, 64, 65, 66, 68, 69, 70, 72, 74, 75, </span>76<span>, </span>77<span>, </span><span>78.</span>
Reil [10]4 years ago
3 0
68 is one. you can multiply it by 2 and another number as well as 1 and itself.
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Rewrite the function by completing the square. 4x^2-4x+1=0
andrey2020 [161]

Do in <u>completing the square method.</u>

{4x}^{2}  - 4x + 1 = 0 \\ 4x^{2}-4x=-1  \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4}  \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4}  \\ x^{2}-x=\frac{-1}{4}  \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2}  \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4}  \\ x^{2}-x+\frac{1}{4}=0  \\ \left(x-\frac{1}{2}\right)^{2}=0  \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}

Now simplify.

x-\frac{1}{2}=0 \\  x-\frac{1}{2}=0  \\  \\  \rightarrow \: x=\frac{1}{2}  \\  \rightarrow \: x=\frac{1}{2}

So, answer is..

\boxed{x=\frac{1}{2} }

Now <u>rewrite</u> the equation.

4 x ^ { 2 } - 4 x + 1 = 0 \\  \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  }

<u>Verification :-</u>

4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-\frac{4}{2}+1=0  \\ 1-2+1=0  \\ -1+1=0  \\ \underline{ 0 = 0} \:  \\  \dashrightarrow \text{true}

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