All categories

3 years ago

Find x 4 over 3 = 8 over x

Mathematics

1 answer:

never [62]3 years ago

4 0

Answer:

x = 6

Step-by-step explanation:

Given

$\frac{4}{3}$ = $\frac{8}{x}$ ( cross- multiply )

4x = 24 ( divide both sides by 4 )

x = 6

You might be interested in

Tom,Scott and dawn sold cookies at the school fair.

aleksklad [387]

First of all work out how many tom and scott sold.
tom sold 60% of 90 cookies which is 54.
scott sold 2/3 of 150 cookies which is 100.
altogether the three of them sold 54+100+46 cookies which is 200.
Dawn sold 46 of these 200 cookies. To work out the percentage we have both the numbers to get 23 out of 100. We halved those numbers because a percentage is out of 100 we halved it to get it out of 100.
so 23 out of 100 is 23% so dawn sold 23%of the cookies.

Hope this helps :)

3 0

3 years ago

Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's

enyata [817]

Answer:

The correct answer is " $\frac{2}{7}$ ".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

$n(A) = 20$

B : final A,

$n(B) = 13$

Didn't start,

$n(A^c \cap B^c) = 12$

Now,

⇒ $n(A \cup B)=35-12$

$=23$

then,

⇒ $n(A \cup B)=20+13-23$

$=10$

hence,

The probability will be:

⇒ $P(A \cap B)=\frac{10}{35}$

⇒ $=\frac{2}{7}$

7 0

2 years ago

........................

omeli [17]

it would be C i think hope this helps

5 0

3 years ago

Read 2 more answers

Could you please help me to solve this query??

galina1969 [7]

Answer:

Show me problem

Step-by-step explanation:

I need a problem to solve it

3 0

2 years ago

Simultaneous equations 5x+y=28 x+y=2

ludmilkaskok [199]

Answer:

Step-by-step explanation:

$5x + y = 28$

$x + y = 8$

Solve the equation for y by moving 'x' to R.H.S and changing its sign

$5x + y = 28$

$y = 2 - x$

Substitute the given value of y into the equation 5x + y = 28

$5x + 2 - x = 28$

Solve the equation for x

Collect like terms

$4x + 2 = 28$

Move constant to R.H.S and change its sign

$4x = 28 - 2$

Subtract the numbers

$4x = 26$

Divide both sides of the equation by 4

$\frac{4x}{4} = \frac{26}{4}$

Calculate

$x = \frac{26}{4}$

Reduce the numbers with 2

$x = \frac{13}{2}$

Now, substitute the given value of x into the equation y = 2 - x

$y = 2 - \frac{13}{2}$

Solve the equation for y

$y = - \frac{9}{2}$

The possible solution of the system is the ordered pair ( x , y )

-------------------------------------------------------------

Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

$5 \times \frac{13}{2} - \frac{9}{2} = 28$

$\frac{13}{2} - \frac{9}{2} = 2$

Simplify the equalities

$28 = 28$

$2 = 2$

Since , all of the equalities are true, the ordered pair is the solution of the system.

$(x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2})$

Hope this helps....

Best regards!!

5 0

3 years ago

Read 2 more answers