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natta225 [31]
3 years ago
15

Can someone help me with this?

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Step-by-step explanation:

The formula for the volume of a sphere is V = 4/3 πr³.

So

Given

Volume (v) = 57ft³

v =  \frac{4}{3} \pi {r}^{3}

57 =  \frac{4}{3}  \times 3.14 \times  {r}^{3}

57 = \frac{12.56}{3} \times    {r}^{3}

57 = 4.19 \times  {r}^{3}

{r}^{3}  =  \frac{57}{4.19}

{r}^{3}  = 13.6

r =  \sqrt[3]{13.6}

Therefore r = 2.4 ft

I gave my answers by rounding off. so if you don't round off then it's answer is 2.3 ft

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James is playing his favorite game at the arcade. After playing the game 333 times, he has 888 tokens remaining. He initially ha
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Answer:

t(g)= -4g + 20

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James is playing his favorite game at the arcade. After playing the game 3 times, he has 8 tokens remaining. He initially had 20 tokens, and the game costs the same number of tokens each time. The number tt of tokens James has is a function of gg, the number of games he plays

Solution

Let

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t= No. of tokens James has.

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y=mx + b

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m = Slope of line,

b = y-intercept.

Before James started playing the games, he has a total of 20 tokens.

That is, when g=0, t=20

After James played the games 3 times, he has 8 tokens left

That is, when g=3, t=8

(x,y)

(0,20) (3,8)

m=y2-y1 / x2-x1

=(8-20) / (3-0)

= -12 / 3

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y=mx + b

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3 0
3 years ago
rectangle with a perimeter of 1110 meters, this rectangular shape is 30 meters longer than 6 times its width. find its dimension
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Answer:

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The perimeter of the rectangle = 1110 meters

Let the width of the rectangle = k meters

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⇒ 1110 = 2( k + (6k + 30))

or, 1110 = 14 k + 60

or, 14 k = 1110 - 60 = 1050

⇒ k = 1050/14 = 75

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6 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
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Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

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length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

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Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

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If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

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= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

8 0
3 years ago
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