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Tomtit [17]
3 years ago
13

Joseph built a model of a pyramid where the base of the pyramid is a square. If the base has an area of 49 cm2 (squared), what i

s the side length of the base?
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

7 cm

Step-by-step explanation:

We are told that the pyramid has a square base of an area of 49 cm².

Therefore, the side length of the base of the pyramid is still the same as the side length of a square having an area of 49 cm².

Area of a square = s², where s is the side length of the square.

The side length of the base can be gotten using the following equation,

s^2 = 49

Solve for s by looking for the share root of both sides.

\sqrt{s^2} = \sqrt{49}

s = 7

The side length of the base = 7 cm

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<span> </span>

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