Question

Joseph built a model of a pyramid where the base of the pyramid is a square. If the base has an area of 49 cm2 (squared), what is the side length of the base?

Answer 1

Answer:

7 cm

Step-by-step explanation:

We are told that the pyramid has a square base of an area of 49 cm².

Therefore, the side length of the base of the pyramid is still the same as the side length of a square having an area of 49 cm².

Area of a square = s², where s is the side length of the square.

The side length of the base can be gotten using the following equation,

$s^2 = 49$

Solve for s by looking for the share root of both sides.

$\sqrt{s^2} = \sqrt{49}$

$s = 7$

The side length of the base = 7 cm