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nikitadnepr [17]
3 years ago
11

What is an appropriate scale for $35

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0

A bar graph. This would be what you would use. I don't know if I misinterpreted your question, but let me know if you still need help. I hoped I helped!

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QUESTION 8 The probability of concluding that assignable variation exists when only random variation is present is: (I) the prob
Juliette [100K]

Answer:

I, II, and IV

Step-by-step explanation:

(I) the probability of a Type I error.

(II) known as the alpha risk.

(IV) the sum of probabilities in the two tails of the normal distribution.

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What the perimeter is ?
tigry1 [53]

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2nd one

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How do you answer this?
lidiya [134]
(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 
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7 0
4 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
gulaghasi [49]

Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

P(A|B)=\frac{1}{3}

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

4 0
4 years ago
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