Question

What is the standard equation with center (4, -5) and radius 11

Answer 1

Answer:

i took a text on this its 1-

Step-by-step explanation:

hope that helps if im wrong im so sorry

Answer 2

Answer:

$(x-4)^2+(y+5)^2=121$

Step-by-step explanation:

The standard equation of a circle is:

$(x- h)^2 + (y- k)^2 = r^2$

where (h,k) is the center, and r is the radius.

We know that (4,-5) is the center, and 11 is the radius.

Therefore, 4 is h, -5 is k, and 11 is r. Substitute them into the equation

$(x-4)^2+(y--5)^2=11^2$

Solve the exponent

$(x-4)^2+(y+5)^2=121$