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dezoksy [38]
3 years ago
5

Two of the Boy Scouts (exercise 19), Tom and Jerry, are weightlifters. They carry 50 lb. per trip. How many trips will each scou

t have to make?
Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

is the the whole question ?

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If a histogram is right skewed, which will be greater the mean or the median? Type a single word answer in the space
Mandarinka [93]

Answer:

Mean is greater

Step-by-step explanation:

For a skewed distribution, then the tail is longer to one side from the center than to the other. In a right skewed distribution, the tail is longer to the right.

When a distribution is skewed, the mean will be closer to the tail Than the median. Therefore. For a right skewed histogram, the mean is closer to the tail of the histogram and hence closer to the right. Once this happens, values closer to the right of a distribution are higher (number line). Thus the mean will be greater than the median.

8 0
3 years ago
Emily has 7 cups of water in a jug.If she drinks 2/3 of a cup every hour.How long would it take her to drink the whole jug
zepelin [54]

It would take her 10.5 hours to drink the whole jug.

Step-by-step explanation:

Given,

Cups of water in jug = 7

Water drunk every hour = \frac{2}{3} of cup

Let,

x be the number of hours.

According to given statement;

\frac{2}{3}x=7

Multiplying both sides by \frac{3}{2}

\frac{3}{2}*\frac{2}{3}x=7*\frac{3}{2}\\x=\frac{21}{2}\\x=10.5

It would take her 10.5 hours to drink the whole jug.

Keywords: fractions, multiplication

Learn more about fractions at:

  • brainly.com/question/6459599
  • brainly.com/question/6649771

#LearnwithBrainly

8 0
3 years ago
Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)                  

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t    Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Discounts: there are 125,000 American soldiers in Iraq . 25% are infantry. From the rest 40% are reservist. How many reservist a
Bond [772]
 there are 87350 reservist

7 0
3 years ago
Evaluate (a + b)2 for a = 2 and b = 3
IgorLugansk [536]
The answer is (2+3)=5
3 0
3 years ago
Read 2 more answers
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