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Tomtit [17]
3 years ago
6

What is the Inverse function of y = 2x + ln(x)?

Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0
Y = 2x + ㏑(x)
x = 2y + ln(y)
jenyasd209 [6]3 years ago
3 0
The inverse function of y = 2x + ln (x) can be determined by explicitly expressing the equation in terms of x. In this case, it is already been done. Then, interchange the variables: x = 2 y + ln (y), This is the most simplified expression
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Pls answer fast i need help
juin [17]

Do it by your self  ok ???

6 0
3 years ago
Read 2 more answers
2x-2y=22 find the value of y when x equals 2
11111nata11111 [884]

Answer:

y = -9

Step-by-step explanation:

Step 1: Substitute x

2(2) - 2y = 22

Step 2: Isolate y

-2y = 18

Step 3: Divide by -2

y = -9

And you have your final answer!

8 0
4 years ago
Read 2 more answers
9x^2+30x+25=0 graphed
pogonyaev

The graphical representation is give in image

8 0
3 years ago
A. Use substitution and show work
Alja [10]
A) 2x -3(3x -7) = 7 . . . . substitute for y
.. -7x = -14 . . . . . . . . . . . subtract 21
.. x = 2 . . . . . . . . . . . . . divide by -7
.. y = 3*2 -7 = -1 . . . . . . substitute for x
(x, y) = (2, -1)


B) 5(5x -2y) -2(3x -5y) = 5(8) -2(1) . . . . subtract 2 times 2nd equation from 5 times 1st
.. 19x = 38 . . . . simplify
.. x = 2 . . . . . . . divide by 19
.. y = (5x -8)/2 = 1 . . . . solve 1st equation for y, substitute x
(x, y) = (2, 1)


C) See the first graph.
(x, y) = (-4, 1)


D) See the second graph.
(x, y) = (3, 2)

6 0
3 years ago
Find the measure of the missing side. Round your answer to the nearest tenth. (PYTHAGOREAN THEOREM)
Burka [1]

Answer:

Rounded to the nearest tenth, the length of the missing side is 5.4 in.

Step-by-step explanation:

According to the Pythagorean theorem, a^{2}+b^{2}=c^{2}, where c is the length of the hypotenuse (the longest side), a and b are the lengths of the other two sides. We can use this to solve for the length of the hypotenuse of the right triangle shown in your question (the missing side):

2^{2}+5^{2}=c^{2}

This simplifies to 29=c^{2}. Now to solve for c (the length of the hypotenuse), we just take the square root of both sides of the equation and solve like so:

\sqrt{29} =\sqrt{c^{2}}

This simplifies to c≈5.4 in.

7 0
3 years ago
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