How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will
be exceeded in a given week is only 0.13
1 answer:
Answer:
$425.6 is the amount that needs to be budgeted
Step-by-step explanation:
P(Y >y)=0.1
3
P(
(Y − µ
)/σ > (y − 400
)/20 )=0.1
3
P(Z >( y − 400
)/20 )=0.1
3
(y − 400
)/20
≈ 1.28
y ≈ (1.28)(20) + 400
y ≈ 425.60
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