All categories

3 years ago

IN A RECTANGLE ABCD, BD=34 AND OC=3X+5 WHAT IS THE VALUE OF X

Mathematics

1 answer:

stiv31 [10]3 years ago

4 0

Answer:

The rectangle has sides AB, BC, CD, and AD. Then AC and BD are diagonals of the rectangle. The diagonals have the same length.

AC = BD

3x + 15 = 4x - 5

Solve the equation for x.

x = 20

Plug this value of x back into any of the expressions.

Step-by-step explanation:

You might be interested in

Am I correct? Will give brainliest!!

nevsk [136]

Yes that would be the correct answer

7 0

3 years ago

Read 2 more answers

5x + 5y = -5 when y = 1<br><br> solve for x in <br><br> 10 points .

san4es73 [151]

Step-by-step explanation:

5x + 5y = -5 , when y = 1

5x + 5.1 = -5

5x + 5 = -5

5x = -5 - 5

5x = -10

x = -10/5

x = -2

4 0

2 years ago

State the equation of the line in y = mx + b form.

gtnhenbr [62]

Your slope is wrong! Your slope is going to be 3/2, or C for the first problem. Your y intercept is wrong! Your Y- intercept is actually (0, -1.3) or B for the second problem.
Your equation is going to be
y= 3/2x-1.3

4 0

3 years ago

Will give brainliest if right, please help me with my homework

Rus_ich [418]

Answer:

Step-by-step explanation:

6 0

3 years ago

1. Consider the data set 1,2,3,4,5,6,7,8,9.

ivanzaharov [21]

Answer: a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

$\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5$

Median = $(\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5$

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

$\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15$

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0

3 years ago