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KiRa [710]
3 years ago
6

Need help with following questions

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

a) no solution; b) x = 1; c)  no solution; d) no solution

Step-by-step explanation:

Next time, please be more specific regarding what kind of help you want.  In this case, it'd be "Solve for x."

2x+5=2x-4 has the term 2x on both sides; we can eliminate this by subtracting 2x from both sides.  But this leads to 5 = -4, which is never true.  This equation has no solution.

2x+6=15x-7 can be rewritten as 13 = 13x.  Dividing both sides by 13, we get x = 1.  The solution is x = 1.

2x+6=8+2x is similar to 2x+5=2x-4 in that both sides have the "2x" term, and 6≠8.  No solution.

x+2y=5=x+3y=8 has two variables (x and y).  

Subtracting 2y from both sides results in:   x = 5 = x+y = 8.  This is not possible, because it states that 5 = 8.  No solution (or possible mistake in copying down this problem).

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444+984 wait the answer
neonofarm [45]

Answer:

1428

Step-by-step explanation:

4 0
4 years ago
The front face of Ivan's MP3 player is a rectangle that is 2 1/2 inches long the width is 7/8 of the length what is the area of
Serggg [28]

Answer:

Therefore,

Are of the front face of Ivan's MP3 player is 2.1875 inches².

Step-by-step explanation:

Given:

The front face of Ivan's MP3 player is a rectangle

Let the length of a front face of Ivan's MP3 player be

Length=2\dfrac{1}{2}=2.5\ inches

and Width of front face of Ivan's MP3 player be

Width=\dfrac{7}{8}=0.875\ inches

To Find:

Area of front face of Ivan's MP3 player =?

Solution:

We have area of rectangle given as

\textrm{Area of Rectangle}=Length\times Width

Substituting the given values we get

\textrm{Area of front face of Ivan's MP3 player}=2.5\times 0.875=2.1875\ inches^{2}

Therefore,

Are of the front face of Ivan's MP3 player is 2.1875 inches².

3 0
3 years ago
For the first five legs of a bicycle race, Elena was 32 second,5 second,10 seconds, 8 seconds, and 12 seconds behind the leader.
Helga [31]
1 minute and 10 seconds (70seconds in total)
3 0
3 years ago
Read 2 more answers
Round 431,857 to the nearest ten thousand
Alex Ar [27]

Answer:

i don' think you can

Step-by-step explanation:

3 0
3 years ago
WILL MARK BRAINLIEST IF CORRECT!!!
wlad13 [49]

I got C. 92.08

I'm not 100% sure I did this right, but I took the money gained between years nine and eleven and divided it by 2. I tried a few other ways, but none of my answers were choices.

4 0
3 years ago
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