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3 years ago

For what value of x does m 1=90°?

Mathematics

1 answer:

HACTEHA [7]3 years ago

3 0

Answer:

x=70

Step-by-step explanation:

Angle 1 will be 90° when it subtends a 180° arc. That means the sum of 100° and (x+10) must be 180°, so (x+10) = 80°.

We assume this is intended to mean ...

... (x +10)° = 80° . . . . . note the ° symbol added outside parentheses

... x +10 = 80 . . . . . divide by °

... x = 70 . . . . . . . . .subtract 10

_____

If the intent is (x+10°) = 80°, then x=70°.

_____

Comment on the numbers here

Units need to be properly specified in problems of this nature. As written, we probably should assume that 10 is radians, and x is a large negative number, about -8.60374 (radians), or -492.958°.

A number of radians is a "pure number." It has no units. The term "radians" is used to signify that the number is considered to be an angle measure.

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-2|7 - 9c| + 7 = -15 Solve for C

IgorLugansk [536]

Solve for c by simplifying both sides of the equation, then isolating the variable.

Exact form: c = -4/9, 2

Decimal form: c = -.4, 2

5 0

3 years ago

Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.

ipn [44]

Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

3(8i + 15j + k) - 2(2i – 5j + 9k)

Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)

3(8i + 15j + k) = 24i + 45j + 3k

-2(2i - 5j + 9k) = -4i + 10j - 18k

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Simplify. Combine like terms

24i - 4i + 45j + 10j + 3k - 18k

(24i - 4i) + (45j + 10j) + (3k - 18k)

20i + 55j - 15k is your answer, or (C)

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hope this helps

5 0

3 years ago

Read 2 more answers

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

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murzikaleks [220]

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3 years ago

How can I factor 16w^2-56w+49

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4 years ago