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shusha [124]
3 years ago
8

Problem Situation: Susan is making a large batch of salsa. She can spend no more than $30 on ingredients. She buys all of the in

gredients except for tomatoes for $6.50. Tomatoes cost $2 per pound. How many pounds of tomatoes, x, can she buy? Inequality That Represents This Situation: 30≥6.50+2x To solve the inequality, you can begin by solving the equation as shown. Drag a diagram to each row of the table to show which number line represents all of the solutions for the inequality and which number line represents all of the solutions for the problem situation.

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

The answer in the procedure

Step-by-step explanation:

Let

x------> the pounds of tomatoes

we know that

The inequality that represent the situation is

30\geq 6.50+2x

solve for x

Subtract  6.50 both sides

30-6.50\geq 2x

23.50\geq 2x

Divide by 2 both sides

23.50/2\geq x

Rewrite

x\leq 11.75\ pounds

so

<em>All the solutions for the inequality </em>

The interval ------> (-∞, 11.75]

All real numbers less than or equal to 11.75

In a number line is the shaded area to the left at x=11.75 (close circle)

see the attached figure N 1

<em>All the solutions for the problem situation </em>

The interval ------> (0, 11.75]

All real numbers greater than zero and less than or equal to 11.75

In a number line is the shaded area between the number zero (open circle) and the number x=11.75 (close circle)

see the attached figure N 2  

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Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.  

(b) Determine the scale factor from the first map to the second map.

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(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

Length =4cm <em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>

(b) The scale factor

The scale factor (k) is calculated as:

k = \frac{New\ Length}{Old\ Length}

k = \frac{4cm}{8cm}\\

k = 0.5

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

k = \frac{New\ Length}{Old\ Length}

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

New\ Length = k * Old\ Length

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New\ Length = 0.5 * 5cm = 2.5cm

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

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