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3 years ago

Solve the division problem. -1 3/5 divide (-2/3) write as a mixed number.

Mathematics

1 answer:

kodGreya [7K]3 years ago

6 0

First you make -1 3/5 into an improper fraction, -8/5

Since you're dividing a fraction by another fraction you'd change it to -8/5 × -3/2

(Don't forget to flip -2/3 to -3/2)

when you multiply it it'd be 24/10

(It is a positive number because when you multiply two negative numbers it becomes positive)

24/10 as a mixed fraction is 2 1/5

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If f(x)=3x3+5x2-4, then what is the remainder when f(x) is divided by x-1

Fed [463]

Answer:

Step-by-step explanation:

If you divide a polynomial f(x) by a linear binomial (x - q), then a remainder is equal to f(q).

We have the polynommial:

$f(x)=3x^3+5x^2-4$

and the linear binomial:

$x-1\to q=1$

Calculate f(1) <em>/substitute x = 1/:</em>

$f(1)=3(1)^3+5(1)^2-4=3(1)+5(1)-4=3+5-4=4$

3 0

3 years ago

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly and at a constant rate. After 8 88 mon

Aliun [14]

Answer:

Equation for the relationship between the weight and number of months -

$W(t) = W(0) + 6 * t$

Step-by-step explanation:

Given

The initial weight of young sumo wrestler just before he decide to gain more weight is equal to $90$ kilo grams.

The new weight of young sumo wrestler after eight months is equal to $138$ kilo grams.

Weight gained by sumo wrestler during the period of eight months

$138 -90\\= 48$

The rate at which weight was gained

$\frac{48}{8}$

$6$ kilo grams per month

Let W(t) depict the weight after 8 months

t depict the time period in moths

So the equation would be

$W(t) = W(0) + 6 * t$

Where

$W(0) =$ Initial weight before 8 months

$t =$ time in months

3 0

3 years ago

HELP HWLP HELP please

alexandr1967 [171]

Answer: 12x

Step-by-step explanation: 3x times 4x = 12x

4 0

3 years ago

Please answer all 3 questions

Sonja [21]

The residuals of the linear regression equation are 0.329, -0.346, 0.064, -0.326, 0.049, -0.286, -0.161, 0.214, 0.429 and 0.059

<h3>How to determine the residuals?</h3>

The regression equation is given as:

y = 0.005x + 3.111

Next, we calculate the predicted values (y) at the corresponding x values.

So, we have:

y = 0.005 * 4 + 3.111 = 3.131

y = 0.005 * 3 + 3.111 = 3.126

y = 0.005 * 5 + 3.111 = 3.136

y = 0.005 * 3 + 3.111 = 3.126

y = 0.005 * 8 + 3.111 = 3.151

y = 0.005 * 15 + 3.111 = 3.186

y = 0.005 * 10 + 3.111 = 3.161

y = 0.005 * 15 + 3.111 = 3.186

y = 0.005 * 6 + 3.111 = 3.141

The residuals are then calculated using:

Residual = Actual value - Predicted value

So, we have:

y = 3.46 - 3.131 = 0.329

y = 2.78 - 3.126 = -0.346

y = 3.2 - 3.136 = 0.064

y = 2.8 - 3.126 = -0.326

y = 3.2 - 3.151 = 0.049

y = 2.9 - 3.186 = -0.286

y = 3 - 3.161 = --0.161

y = 3.4 - 3.186 = 0.214

y = 3.57 - 3.141 = 0.429

y = 3.2 - 3.141 = 0.059

Hence, the residuals of the linear regression equation are 0.329, -0.346, 0.064, -0.326, 0.049, -0.286, -0.161, 0.214, 0.429 and 0.059

See attachment for the residual plot.

The residual plot shows that the linear model from the regression calculator is a good model because the points are not on a straight line