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liq [111]
3 years ago
15

HELPP !!!!!! THEY ALL GO SOMEWHERE THERE SHOULDNT BE ANYLEFT

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
6 0
A) you pick the saultion up 4 right 3 would be so you have the 4th on the right of the first the 3 Ads onto the 4 bye devided bye 3x4 so 4 right and up three is the first box I hoped abhelped
lutik1710 [3]3 years ago
3 0
A.) (3, 4) = "right 3 up 4" [ Option A, C ]

B.) (-3, 4) = "left 3 up 4" [ Option B, D ]

C.) (4, -3) = "right 4 down 3" [ Option E ]

Hope this helps!
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Can you help me with this its easy
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I put a ladder 1.5m away from a tree. the ladder is inclined at 70 degrees about the horizontal. What is the height of the tree?
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3 years ago
Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
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