Answer:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
The value of r is always between 
And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

So then the best conclusion for this case would be:
c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.
Step-by-step explanation:
For this case we know that the correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. And we know that we use the height x of a child to predict the weight y of the child
We need to rememeber that the correlation is a measure of dispersion of the data and is given by this formula:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
The value of r is always between 
And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

So then the best conclusion for this case would be:
c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.
Answer:
- 150
Step-by-step explanation:
5×-30?-----) -150 is the answer
The result is: {5,6,9}
Step-by-step explanation:
Given
U = {0,1,2,......,10}
A = {5,6,9}
B = {0, 6, 7, 10}
We have to find
(A∩B)U(A∩B')
First of all,
<u>B':</u>
B' = U -B = {0,1,2,......,10} - {0, 6, 7, 10}
= {1,2,3,4,5,8,9}
<u>A∩B':</u>
A∩B' = {5,6,9} ∩ {1,2,3,4,5,8,9}
= {5,9}
<u>A∩B:</u>
A∩B = {5,6,9} ∩ {0, 6, 7, 10}
={6}
At the end we have to find union
(A∩B)U(A∩B') = {6} U {5,9}
(A∩B)U(A∩B') = {5,6,9}
Hence,
The result is: {5,6,9}
Keywords: Sets , Union
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