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3 years ago

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Mathematics

1 answer:

9966 [12]3 years ago

7 0

Answer:

D) b = $\frac{S-2ac}{2a + 2c}$

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = $\frac{S-2ac}{2(a + c)}$

Finally, multiply out the denominator:

b = $\frac{S-2ac}{2a + 2c}$

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If 0.142857142857......is expressed in the form m/n, then what is the value of (2m + n)?

frosja888 [35]

Answer:

The value will be: 1,285,713

Step-by-step explanation:

We have the number:

N = 0.142857...

Such that we have 6 decimals after the decimal point that repeat infinitely.

Then let's start by multiplying our number by 1,000,000 (same number of zeros as decimals after the decimal point)

Then we get:

1,000,000*N = 142,857.142857...

Now let's subtract N from both sides:

1,000,000*N - N = 142,857.142857... - 0.142857...

999,999*N = 142,857

Now let's isolate N

N = 142,857/999,999

Here is our number expressed in the form m/n, where:

m = 142,857

n = 999,999

Then the value of (2*m + n) is:

(2*142,857 + 999,999) = 1,285,713

5 0

3 years ago

Consider the following polynomial.

vfiekz [6]

Answer:

The equivalent factored form of this equation is (x² + 49)(x - 6)

Step-by-step explanation:

x³ - 6x² + 49x - 294

First, group the first and second terms together and group the last two terms together.

(x³ - 6x²) + (49x - 294)

Find the greatest common factor of both parentheses and factor them.

x²(x - 6) + 49(x - 6)

Now, since the two terms in the parentheses are the same, then we have factored the equation correctly.

So, the factored form of the equation is (x² + 49)(x - 6)

3 0

2 years ago

Read 2 more answers

Y(y + 4) - y 2 = 6 is a quadratic equation. True or False

Ugo [173]

Y(y + 4) - y2 = 6
y2 + 4y - y2 = 6
4y = 6 ⇒ False

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3 years ago

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What is the range of the function y = x ^2?

VikaD [51]

Range: [0, ∞), {y|0 ≤ y}

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3 years ago

Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC Please solve!

sukhopar [10]

If m ACD = 30 => m DCB = 60.
In triangle ACD:
$sin 30^{o}=sin \frac{AD}{AC} =\ \textgreater \ \frac{1}{2} = \frac{8}{AC} =\ \textgreater \ AC=16
$
$CD= 8 \sqrt{3}$
$BC= 16\sqrt{3}$
AC^{2}+CB^{2}=AB^{2} => AB= $\sqrt{1024}$ =32.
=> P=16+32+ $16 \sqrt{3}$ =48 + $16 \sqrt{3}$ .

8 0

3 years ago