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Rufina [12.5K]
3 years ago
10

One month, ruby worked 6 more hours than Issac, and Svetlana worked 4 times as many hours as Ruby. Together they worked 126 hour

s. Find the number of hours each person worked.
Mathematics
1 answer:
garik1379 [7]3 years ago
8 0
Ruby's hours will represent x+6
Svetlana's hours will represent 4(x+6)
Issac will represent x.

The equation would read:
x+(x+6)+(4(x+6))=126
x+x+6+4x+24=126
6x+30=126
Subtract 30 from both sides.
6x=96
Divide 6 on both sides to get x by itself.
x=16

So:
Issac worked 16 hours
Ruby worked 22 hours
Svetlana worked 88 hours.

To check your answer, plug in the values:
16+22+88=126
126=126

Hope this helps.
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Hi guys, can anyone help me with this triple integral? Many thanks:)
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Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

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Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

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