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4 years ago

How do I find decay?.........

Mathematics

1 answer:

Bess [88]4 years ago

5 0

Answer:

Step-by-step explanation:

the line slopes steeply and isnt constant

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Help please solve for y

viva [34]

Answer:

y = 15

Step-by-step explanation:

(6 (15) - 10) =

(90 - 10) =

(6 (15) + 10) =

(90 + 10) =

100 + 80 = 180

Therefore y is equal to 15

Hope It Helps...

7 0

3 years ago

2. The logo shown below was created by splitting a circle into 6 equal sections. Raphael is creating a stage-sized version of th

andrew11 [14]

From the shaded diagram, Raphael will need 3 of the 6 equal portions, or exactly 1/2 of the area of the circle. Given a radius of 12 ft, knowing that the area of any given circle is $\pi r^2$ , and knowing that the area of the fabric needs to be half of the total area, we can set up the equation for the area of the fabric $A$ :

$A= \frac{1}{2}\pi (12)^2$

Simplifying, we find that the area of the fabric is exactly

$\frac{1}{2} \pi (144)= \frac{144}{2} \pi=72\pi$ ft.² Using the approximation of 3.14 for π, we get an area of approximately $72(3.14)=226.08$ ft² of fabric.

6 0

4 years ago

Write the ratio as a fraction in simplest form

nignag [31]

Answer:

$\frac{80}{16}$

5 0

3 years ago

Read 2 more answers

If a leaky faucet drips 10 ounces of water per minute how many gallons per hour is that

Anna [14]

10 times 60 is 600 so the awnser 600

8 0

3 years ago

Pls solve this question

just olya [345]

Answer:

${( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } }$

Or ;

${( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} }$

3 0

2 years ago