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Sindrei [870]
3 years ago
12

How do I find x in this question. Please help I'm very confused.

Mathematics
1 answer:
seropon [69]3 years ago
8 0
X=99 and theres no question
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hoa [83]

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Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
Anika [276]

Answer:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19



Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

2x^{2}-5x-1=0

a=2\\b=-5\\c=-1

Then you have:

 x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}

3. Therefore, you obtain the following result:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19


4 0
3 years ago
Read 2 more answers
Simplefly the problem 1/2x/45>61
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x>5490

x

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2 years ago
mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the
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What is the reason for number 4 and 5?
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