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Shalnov [3]
3 years ago
11

Solve: (1/x)+6 = 5/sqrt(x)

Mathematics
1 answer:
Semenov [28]3 years ago
4 0
<em>Solve: </em>\frac{1}{x} + 6 = \frac{5}{\sqrt{x}}

Start by squaring both sides to eliminate the square root.
(\frac{1}{x} + 6)^{2} = \frac{25}{x}

Expand the left hand side.
\frac{1}{x^{2}} + \frac{12}{x} + 36 = \frac{25}{x}

Simplify.
\frac{1}{x^{2}} - \frac{13}{x} + 36 = 0
\frac{1 - 13x + 36x^{2}}{x^{2}} = 0

Solve for x.
36x^{2} - 13x + 1 = 0
36x^{2} - 9x - 4x + 1 = 0
9x(4x - 1) - (4x - 1) = 0

(9x - 1)(4x - 1) = 0
\therefore x = \frac{1}{9}, \frac{1}{4}
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(-x+3)-(x-5) please show work​
Lina20 [59]

simplify each term

apply the distributive property

-X+3+(-X- -5)

multiple -1 by -5

-X+3+(-x+5)

remove unnecessary parentheses

-x+3-×+5

subtract x from -x

-2x+3+5

add 3 and 5.

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5 0
2 years ago
My brother is currently three times as old as me, but in five years, my brother
wolverine [178]

Answer: Your brother is 15 years old right now.

Step-by-step explanation:

Let be "m" your currently age and "b" your brother's currently age.

Knowing that right now he is three times (this indicates multiplication) as old as you, you can write the following equation:

b=3m

In five years your age will be:

 m+5

And your brother's age will be:

b+5

Then, if in five years, your  brother will be twice as old as you, you can set up the second equation:

b+5=2(m+5)

Then, the System of equations is:

\left \{ {{b=3m} \atop {b+5=2(m+5)}} \right.

 Apply the Substitution method and substitute the first equation into the second one and solve for "m":

3m+5=2(m+5)\\\\3m+5=2m+10\\\\m=10-5\\\\m=5

Substitute the value of "m" into the first equation and evaluate in order to find "b":

b=3(5)\\\\b=15

4 0
3 years ago
Four different positive integers have a product of 110.<br>What is the sum of the four integers?​
BigorU [14]
<h3>Answer:  19</h3>

Explanation:

Let's break 110 down into its prime factors

110 = 11*10

110 = 11*2*5

110 = 2*5*11

We have three different prime factors that multiply to 110. However, the instructions say there are 4 integers that multiply to 110. To fix this, we can say

110 = 1*2*5*11

now we see that 1,2,5 and 11 multiply out to 110

They add to 1+2+5+11 = 3+16 = 19

3 0
2 years ago
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