Answer:
I don’t know
Step-by-step explanation:
Plz clairify
Answer:
5/12
7/12
125/36 = 3,47%
50/11 = 4,54%
Step-by-step explanation:
Probability a black sock is selected when a person chooses 1 sock = 5/12
Probability a white or brown sock is selected when a person chooses 1 sock =
7/12
Probability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%
Pobability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%
One hour = 60 minutes
60-15=45 so I would just add your 45 minutes to your 2:15
2:15+:45= 3:00
so your answer will be 3:00 :)
Answer:
Step-by-step explanation:
The graph shows the solution (-6,2)
i.e at x= -6 y=2
Analysis of each of the answers, since we can't write the equation of a straight line with only that information i.e the single point
Then,
Option 1
1. 2x - 3y = -6
x= -6 y=2
Then let insert x=-6 and y =2
2(-6)-3(2)
-12-6
-18.
Since -18 ≠ -6, then this is not the equation of the line and doesn't make up the system
Option 2
2. 4x - y = 26
Inserting x=-6 and y=2
4(-6)-(2)
-24-2
-26
Since -26 ≠ 26, then this is not the equation of the line and doesn't make up the system
Option 3
3. 3x + 2y = -14
Inserting x=-6 and y=2
3(-6)+2(2)
-18+4
-14
Since -14 ≠ -14 then this is the equation of the line and it make up the system.
Option 4
x-y = -2
Inserting x=-6 and y=2
(-6)-(2)
-6-2
-8
Since -8≠ -2, then this is not the equation of the line and doesn't make up the system
Option 5
5. x+y=-4
Inserting x=-6 and y=2
(-6)+(2)
-6+2
-4
Since -4 ≠ -4, then this is the equation of the line and it makes up the system.
Then, there are two option that make up the system
3. 3x + 2y = -14
And
5. x+y=-4
<span>If the clock is held at a
constant 0.0ºc over a period of 24 hours, the clock will be exactly the same as
the perfect clock because it is at a
constant 0.0</span> <span>ºc for 24. Meaning there is
no deviation on its reading</span>
