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romanna [79]
3 years ago
13

Seventy percent of the light aircraft that disappear while in flight in a certain countryare subsequently discovered. Of the air

craft that are discovered,60%have an emer-gency locator, whereas90%of the aircraft not discovered do not have such a locator.Suppose a light aircraft has disappeared.(a)[5 pts]If it has an emergency locator, what is the probability that it will not bediscovered
Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Step-by-step explanation: If we denote the percentage of light aircraft subsequently discovered, and the percentage of which is 70, by the mark <em>P(discovered) = 0.7</em>. Further, if the percentage of those light aircraft that are discovered and have a locator is 60, that is, <em>P(discovered / locator) = 0.6</em>, then the percentage of light aircraft that are not discovered will be <em>P(discovered ' ) = 1 - 0.7 = 0.3</em>. As is the percentage of undiscovered aircraft that do not have a locator <em>P(discovered ' / locator ') = 0.9</em>.

What we need to do is determine the probability that the missing aircraft will not be found and has a locator. So, <em>P(discovered ' / locator) = ?</em>

We will do this as follows. First of all the total percentage of aircraft discovered and having a locator is 0.7 x 0.6 = 0.42. Further, the total percentage of aircraft not discovered and lacking a locator is 0.9 x 0.3 = 0.27. Then the total percentage of aircraft discovered and lacking a locator will be 0.7 - 0.42 = 0.28. Like the total percentage of aircraft not discovered that have a locator is 0.3 - 0.27 = 0.03.

To make all this more obvious, we will show in the table

                                 Locator                     Locator '

--------------------------------------------------------------------------------------------------------------

Discovered          0.42 = 0.7 x 0.6              0.28                             0.70

Discovered '               0.03                  0.27 = 0.9 x 0.3                   0.30

--------------------------------------------------------------------------------------------------------------

                                   0.45                           0.55                             1.00

Then what we're looking for is the probability that the aircraft will not be discovered and has a locator will be:

P = (discovered ' / locator) = P (discovered ' / locator) / P (locator), that is

P = (discovered ' / locator) = 0.03 / 0.45 = 0.06667

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