All categories

4 years ago

FOR ALL PLATO USERS:

Computers and Technology

2 answers:

aleksley [76]4 years ago

6 0

You have to ask you teacher to show you which ones you got wrong and the answers to them.

Black_prince [1.1K]4 years ago

3 0

Answer:

you cant personally

Explanation:

You might be interested in

How do I do a PowerPoint

kirill115 [55]

It is like this: . You just put a circle and that is a power point

4 0

3 years ago

Read 2 more answers

NAME SEARCH In the Chap07 folder of the Student Sample Programs, you will find the following files: GirlNames.txt—This file cont

Tems11 [23]

Answer:

Explanation:

I do not have the files listed in the question so I have made two test files with the same names. This code is written in Python, we are assuming that the names on each file are separated by newlines.

f1 = open("GirlNames.txt", 'r')

f1_names = f1.read()

f1_names_list = f1_names.split('\n')

f2 = open("BoyNames.txt", 'r')

f2_names = f2.read()

f2_names_list = f2_names.split('\n')

print(f1_names_list)

print(f2_names_list)

boy_or_girl = input("Would you like to enter a boy or girl name or both: ").lower()

if boy_or_girl == 'boy':

name = input("Enter name: ")

if name in f2_names_list:

print("Yes " + name + " is in the list of most popular boy names.")

else:

print("No, it is not in the list")

elif boy_or_girl == 'girl':

name = input("Enter name: ")

if name in f1_names_list:

print("Yes " + name + " is in the list of most popular girl names.")

else:

print("No, it is not in the list")

elif boy_or_girl == 'both':

girlname = input("Enter Girl name: ")

if girlname in f1_names_list:

print("Yes " + girlname + " is in the list of most popular girl names.")

else:

print("No, it is not in the list")

boyname = input("Enter name: ")

if boyname in f2_names_list:

print("Yes " + boyname + " is in the list of most popular girl names.")

else:

print("No, it is not in the list")

else:

print("Wrong input.")

4 0

3 years ago

Write the definition of a function divide that takes four arguments and returns no value . The first two arguments are of type i

Nastasia [14]

Answer:

#include <iostream>

using namespace std;

void divide(int numerator, int denominator, int *quotient, int *remainder)

{

*quotient = (int)(numerator / denominator);

*remainder = numerator % denominator;

}

int main()

{

int num = 42, den = 5, quotient=0, remainder=0;

divide(num, den, &quotient, &remainder);

return 0;

}

Explanation:

The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.

To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.

Thanks! :)

8 0

3 years ago

Which of these methods can you use to insert a new row in a worksheet?

vodka [1.7K]

Answer:

I think It should be B

Explanation:

If wrong so please sorry

3 0

3 years ago

Each codec is stored within a file called a(n) ____ file.

frutty [35]

Im like 90% sure its a container file

5 0

3 years ago