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beks73 [17]
3 years ago
11

Write 3,543.21 in word form

Mathematics
2 answers:
valkas [14]3 years ago
7 0

Answer:

three thousand five hundred and forty three and twenty-one hundredths

To work this out you would first look at the place value that is the biggest. In this case it is 3000 then you would convert that into words by looking at its place, lets say in the thousands and the number is a 3. Then it becomes three thousand. you would then do that for each number

Fittoniya [83]3 years ago
3 0

Answer:

three thousand five hundred fourtythree point twentyone

Step-by-step explanation:

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Write the following sentence into an expression using x as your variable: Myrna and Tom collect stamps. Tom has four more than h
balandron [24]

Answer: f(x) = x/2 + 4.

where f(x) is the number of stamps that Tom has, and x is the number of stamps that Myrna has.

Step-by-step explanation:

The statement is:

"Tom has four more than half the stamps that Myrna has"

For how is written, we can model the number of stamps that Tom has as a function f(x).

f(x) represents the number of stamps that Tom has, and x is the number of stamps that Myrna has.

Then:

"four more than a number" is written as:

N + 4 (where N is the number)

"Half the stamps that Myrna has" is written as:

x/2.

Then the whole statement can be modeled as:

f(x) = x/2 + 4.

notice that we have x/2, and f(x) must be a whole number, so Myrna must have an even number of stamps (in that case x/2 will be integer)

8 0
4 years ago
Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
8. a. If A is 5 x 5 matrix and det(A) = 3 then det(2A) = --------- b. If A is 100 x 100 matrix and det( A) = m then det(-A) = --
cricket20 [7]

Answer:

a) det(A)=96; b) det(A)=m;

Step-by-step explanation:

If we have a n \times n matrix A and a constant t \in \mathbb{R}. It holds that \det(tA)=t^n\det(A), hence

(a) If A is a 5x5 matrix and \det(A)=3, then we have

\det(2A)=2^5\cdot \det(A)= 32 \cdot 3=96

(b) If A is 100 \times 100 matrix and \det(A)=m, then we have

\det(-A)=(-1)^{100}\det(A)=(-1)^{100}\cdot m=1 \cdot m = m

5 0
4 years ago
I need help with this problem
zhuklara [117]

Answer:

easy so first 190-15=175  175 lbs. is the light heavyweight class weight limit

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
13.8ft<br> 15.6ft<br> 23.4ft<br> 46.8ft
balandron [24]

Answer:

it is 15.6ft because you need to add 7.8+7.8= 15.6ft

8 0
3 years ago
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