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Alla [95]
3 years ago
11

Which is the graph of linear inequality 6x + 2y > –10?..​

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

Step-by-step explanation:

6x+2y>-10\qquad\text{subtract 6x from both sides}\\\\2y>-6x-10\qquad\text{divide both sides by 2}\\\\y>-3x-5

Change the inequality symbol to the symbol of equation.

y=-3x-5

Choice any two values of x and calculate the values of y:

for x = 0

y=-3(0)-5=0-5=-5\to(0,\ -5)

for x = -2

y=-3(-2)-5=6-5=1\to(-2,\ 1)

Draw the line passing through the given points.

If is < or >, then plot the dot line.

If is ≤ or ≥, then plot the solid line.

We have the sign of an inequality ">". Therefore plot a dot line.

Now shading.

If is < or ≤, then shading to the left.

If is > or ≥, then shading to the right.

We have the sign of an inequality ">'. Therefore shading to the right.

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3 years ago
Colby is making a home video consisting of a 5-minute introduction followed by several short skits. Each skit is 8 minutes long.
Delvig [45]
Colby is making a home video consisting of a 5-minute introduction followed by several short skits. Each skit is 8 minutes long. If colby's video is 133 minutes long how many skits are in his video? 

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4 years ago
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Make w the subject of the formula s = w/a
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Answer:

w = sa

Step-by-step explanation:

Given

s = \frac{w}{a} ( multiply both sides by a to clear the fraction )

sa = w

8 0
3 years ago
How do you simplify (3a^2b) /(5ac) x (10c) /(6ab) given that A, B, C does not equal to 0?
krek1111 [17]

Answer:

  • 1

Step-by-step explanation:

  • (3a²b) /(5ac) x (10c) /(6ab) =
  • (3ab)/(5c) × (5c)/(3ab)
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8 0
3 years ago
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Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ
tensa zangetsu [6.8K]

Answer:    RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= \frac{18+x}{RQ}

⇒ RQ=  \frac{18+x}{tan 75^{\circ}}

Now, In triangle MRQ,

tan 60°= \frac{18+x}{RQ}

⇒ RQ=  \frac{x}{tan 60^{\circ}}

On equating both values of RQ,

\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=2.15470053838

⇒18=2.15470053838x-x

⇒x=15.5884572681≈15.60

Thus RQ=8.99999999999≈8.99


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3 years ago
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