Answer:
The correct answer is Adaptive differential pulse code modulation
Explanation:
Adaptive differential pulse code modulation (ADPCM) is a variant of differential pulse-code modulation (DPCM) that varies the size of the quantization step, to allow further reduction of the required data bandwidth for a given signal-to-noise ratio. The output data rate can be dynamically adjusted between 16 kbit/s and 64 kbit/s in these applications.
Different video files and operating system versions can cause compatibility issues to arise between computer systems.
Since, file formats and operating systems may not be compatible with each other. For example, earlier versions of Windows may not be able to play certain types of video files due to the codecs used to encode them.
<h3>Importance of compatibility between operating system computer systems</h3>
Compatibility between operating systems is important because it allows different computer systems to interact and share resources. This includes sharing of programs, files, and data.
Compatibility also allows users to access applications and services on different platforms. It also enables efficient use of hardware and software resources, as well as efficient use of resources in a network. Compatibility also ensures that computer systems can communicate with each other and can access the same resources. Without compatibility, it would be difficult for computer systems to interact with each other.
What are two compatibility issues that may arise between computer systems while transferring presentations? (Fill in the blank).
Different video files and _____ can cause compatibility issues to arise between computer systems.
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Answer:
import random
a = random.randint(1,10)
b = random.randint(1,10)
answer = a * b
print (str(a) + " X " + str(b) + " = " + str(answer))
Explanation:
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Answer:
Check the explanation
Explanation:
223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.
The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000
Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)
So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26
Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)
and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25
Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)
So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28
